131413112241041 has 4 divisors (see below), whose sum is σ = 134209135905792. Its totient is φ = 128617088576292.

The previous prime is 131413112241011. The next prime is 131413112241043. The reversal of 131413112241041 is 140142211314131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131413112241041 - 2³⁴ = 131395932371857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131413112240995 and 131413112241013.

It is not an unprimeable number, because it can be changed into a prime (131413112241043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1398011832305 + ... + 1398011832398.

It is an arithmetic number, because the mean of its divisors is an integer number (33552283976448).

Almost surely, 2^{131413112241041} is an apocalyptic number.

It is an amenable number.

131413112241041 is a deficient number, since it is larger than the sum of its proper divisors (2796023664751).

131413112241041 is an equidigital number, since it uses as much as digits as its factorization.

131413112241041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2796023664750.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 131413112241041 its reverse (140142211314131), we get a palindrome (271555323555172).

The spelling of 131413112241041 in words is "one hundred thirty-one trillion, four hundred thirteen billion, one hundred twelve million, two hundred forty-one thousand, forty-one".