Base | Representation |
---|---|
bin | 11101111000010100001011… |
… | …110101110001001001000011 |
3 | 122020021222201201202112222212 |
4 | 131320110023311301021003 |
5 | 114211033431112000003 |
6 | 1143254235332252335 |
7 | 36452204255041556 |
oct | 3570241365611103 |
9 | 566258651675885 |
10 | 131413313000003 |
11 | 38966089283461 |
12 | 128a49447710ab |
13 | 58432b7360a48 |
14 | 246461c92c69d |
15 | 102d566385dd8 |
hex | 77850bd71243 |
131413313000003 has 16 divisors (see below), whose sum is σ = 131650218832896. Its totient is φ = 131176624400640.
The previous prime is 131413312999987. The next prime is 131413313000009. The reversal of 131413313000003 is 300000313314131.
It is a cyclic number.
It is not a de Polignac number, because 131413313000003 - 24 = 131413312999987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131413313000009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14962230950 + ... + 14962239732.
It is an arithmetic number, because the mean of its divisors is an integer number (8228138677056).
Almost surely, 2131413313000003 is an apocalyptic number.
131413313000003 is a deficient number, since it is larger than the sum of its proper divisors (236905832893).
131413313000003 is an equidigital number, since it uses as much as digits as its factorization.
131413313000003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18274.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 131413313000003 its reverse (300000313314131), we get a palindrome (431413626314134).
The spelling of 131413313000003 in words is "one hundred thirty-one trillion, four hundred thirteen billion, three hundred thirteen million, three", and thus it is an aban number.
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