Base | Representation |
---|---|
bin | 11101111000010100010001… |
… | …010001000001010111000011 |
3 | 122020021222222002001101020011 |
4 | 131320110101101001113003 |
5 | 114211034122412433103 |
6 | 1143254252343325351 |
7 | 36452206441555405 |
oct | 3570242121012703 |
9 | 566258862041204 |
10 | 131413404030403 |
11 | 389661256a89a0 |
12 | 128a496b150857 |
13 | 58433001839a1 |
14 | 246462aa66b75 |
15 | 102d56e367d6d |
hex | 7785114415c3 |
131413404030403 has 4 divisors (see below), whose sum is σ = 143360077124088. Its totient is φ = 119466730936720.
The previous prime is 131413404030361. The next prime is 131413404030463. The reversal of 131413404030403 is 304030404314131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131413404030403 - 221 = 131413401933251 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131413404030463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5973336546826 + ... + 5973336546847.
It is an arithmetic number, because the mean of its divisors is an integer number (35840019281022).
Almost surely, 2131413404030403 is an apocalyptic number.
131413404030403 is a deficient number, since it is larger than the sum of its proper divisors (11946673093685).
131413404030403 is a wasteful number, since it uses less digits than its factorization.
131413404030403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11946673093684.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 131413404030403 its reverse (304030404314131), we get a palindrome (435443808344534).
The spelling of 131413404030403 in words is "one hundred thirty-one trillion, four hundred thirteen billion, four hundred four million, thirty thousand, four hundred three".
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