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13141412103 = 34380470701
BaseRepresentation
bin11000011110100101…
…00000100100000111
31020220211212220101210
430033102200210013
5203403200141403
610012002022503
7643441105551
oct141722404407
936824786353
1013141412103
115633a91466
122669047a33
1313157849c1
148c945a4d1
1551da86b03
hex30f4a0907

13141412103 has 4 divisors (see below), whose sum is σ = 17521882808. Its totient is φ = 8760941400.

The previous prime is 13141412099. The next prime is 13141412129. The reversal of 13141412103 is 30121414131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13141412103 - 22 = 13141412099 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13141412103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13141412173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2190235348 + ... + 2190235353.

It is an arithmetic number, because the mean of its divisors is an integer number (4380470702).

Almost surely, 213141412103 is an apocalyptic number.

13141412103 is a deficient number, since it is larger than the sum of its proper divisors (4380470705).

13141412103 is an equidigital number, since it uses as much as digits as its factorization.

13141412103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4380470704.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 13141412103 its reverse (30121414131), we get a palindrome (43262826234).

The spelling of 13141412103 in words is "thirteen billion, one hundred forty-one million, four hundred twelve thousand, one hundred three".

Divisors: 1 3 4380470701 13141412103