Base | Representation |
---|---|
bin | 111101001100011100… |
… | …1101101010010110111 |
3 | 110120012111011021210020 |
4 | 1322120321231102313 |
5 | 4123114024032242 |
6 | 140212040100223 |
7 | 12331365656466 |
oct | 1723071552267 |
9 | 416174137706 |
10 | 131414283447 |
11 | 50806a34227 |
12 | 21576464673 |
13 | c513bb4745 |
14 | 65092589dd |
15 | 36420ca6ec |
hex | 1e98e6d4b7 |
131414283447 has 4 divisors (see below), whose sum is σ = 175219044600. Its totient is φ = 87609522296.
The previous prime is 131414283443. The next prime is 131414283557. The reversal of 131414283447 is 744382414131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131414283447 - 22 = 131414283443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131414283399 and 131414283408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131414283443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21902380572 + ... + 21902380577.
It is an arithmetic number, because the mean of its divisors is an integer number (43804761150).
Almost surely, 2131414283447 is an apocalyptic number.
131414283447 is a deficient number, since it is larger than the sum of its proper divisors (43804761153).
131414283447 is an equidigital number, since it uses as much as digits as its factorization.
131414283447 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43804761152.
The product of its digits is 258048, while the sum is 42.
Adding to 131414283447 its reverse (744382414131), we get a palindrome (875796697578).
The spelling of 131414283447 in words is "one hundred thirty-one billion, four hundred fourteen million, two hundred eighty-three thousand, four hundred forty-seven".
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