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13142011411 = 101912896969
BaseRepresentation
bin11000011110101001…
…10010111000010011
31020220220000100111101
430033110302320103
5203403323331121
610012022525231
7643446153034
oct141724627023
936826010441
1013142011411
115634360761
122669296817
131315934719
148c9574a8b
1551db54491
hex30f532e13

13142011411 has 4 divisors (see below), whose sum is σ = 13154909400. Its totient is φ = 13129113424.

The previous prime is 13142011391. The next prime is 13142011429. The reversal of 13142011411 is 11411024131.

13142011411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13142011411 - 27 = 13142011283 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13142011111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6447466 + ... + 6449503.

It is an arithmetic number, because the mean of its divisors is an integer number (3288727350).

Almost surely, 213142011411 is an apocalyptic number.

13142011411 is a deficient number, since it is larger than the sum of its proper divisors (12897989).

13142011411 is a wasteful number, since it uses less digits than its factorization.

13142011411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12897988.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 13142011411 its reverse (11411024131), we get a palindrome (24553035542).

The spelling of 13142011411 in words is "thirteen billion, one hundred forty-two million, eleven thousand, four hundred eleven".

Divisors: 1 1019 12896969 13142011411