Base | Representation |
---|---|
bin | 1011111100111110001000… |
… | …1110100011010101000011 |
3 | 1201112101001120112000002021 |
4 | 2333033202032203111003 |
5 | 3210310010202032003 |
6 | 43541221513502311 |
7 | 2524325333312005 |
oct | 277174216432503 |
9 | 51471046460067 |
10 | 13142100424003 |
11 | 4207596091541 |
12 | 158303aa11997 |
13 | 7443aa756245 |
14 | 33611c5b0375 |
15 | 17bcc99a62bd |
hex | bf3e23a3543 |
13142100424003 has 4 divisors (see below), whose sum is σ = 13142138237080. Its totient is φ = 13142062610928.
The previous prime is 13142100424001. The next prime is 13142100424021. The reversal of 13142100424003 is 30042400124131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13142100424003 - 21 = 13142100424001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13142100424001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18380325 + ... + 19081942.
It is an arithmetic number, because the mean of its divisors is an integer number (3285534559270).
Almost surely, 213142100424003 is an apocalyptic number.
13142100424003 is a deficient number, since it is larger than the sum of its proper divisors (37813077).
13142100424003 is an equidigital number, since it uses as much as digits as its factorization.
13142100424003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37813076.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13142100424003 its reverse (30042400124131), we get a palindrome (43184500548134).
The spelling of 13142100424003 in words is "thirteen trillion, one hundred forty-two billion, one hundred million, four hundred twenty-four thousand, three".
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