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131421103343 = 1011301199043
BaseRepresentation
bin111101001100101001…
…1101110010011101111
3110120012221222202220222
41322121103232103233
54123122300301333
6140212442201555
712331510642535
oct1723123562357
9416187882828
10131421103343
115080a872102
12215787b32bb
13c51543199a
14650a112155
1536429c6298
hex1e994ee4ef

131421103343 has 4 divisors (see below), whose sum is σ = 132722302488. Its totient is φ = 130119904200.

The previous prime is 131421103309. The next prime is 131421103357. The reversal of 131421103343 is 343301124131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131421103343 - 28 = 131421103087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131421106343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650599421 + ... + 650599622.

It is an arithmetic number, because the mean of its divisors is an integer number (33180575622).

Almost surely, 2131421103343 is an apocalyptic number.

131421103343 is a deficient number, since it is larger than the sum of its proper divisors (1301199145).

131421103343 is a wasteful number, since it uses less digits than its factorization.

131421103343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1301199144.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 131421103343 its reverse (343301124131), we get a palindrome (474722227474).

The spelling of 131421103343 in words is "one hundred thirty-one billion, four hundred twenty-one million, one hundred three thousand, three hundred forty-three".

Divisors: 1 101 1301199043 131421103343