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1314211303 = 3142393913
BaseRepresentation
bin100111001010101…
…0100010111100111
310101120220211222201
41032111110113213
510142414230203
6334224035331
744365416556
oct11625242747
93346824881
101314211303
11614924449
12308162b47
1317c372632
14c677dd9d
157a59ae1d
hex4e5545e7

1314211303 has 4 divisors (see below), whose sum is σ = 1356605248. Its totient is φ = 1271817360.

The previous prime is 1314211289. The next prime is 1314211363. The reversal of 1314211303 is 3031124131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1314211303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314211363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21196926 + ... + 21196987.

It is an arithmetic number, because the mean of its divisors is an integer number (339151312).

Almost surely, 21314211303 is an apocalyptic number.

1314211303 is a deficient number, since it is larger than the sum of its proper divisors (42393945).

1314211303 is an equidigital number, since it uses as much as digits as its factorization.

1314211303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42393944.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1314211303 is about 36252.0523970713. The cubic root of 1314211303 is about 1095.3554312758.

Adding to 1314211303 its reverse (3031124131), we get a palindrome (4345335434).

The spelling of 1314211303 in words is "one billion, three hundred fourteen million, two hundred eleven thousand, three hundred three".

Divisors: 1 31 42393913 1314211303