131421405420303 has 4 divisors (see below), whose sum is σ = 175228540560408. Its totient is φ = 87614270280200.

The previous prime is 131421405420289. The next prime is 131421405420311. The reversal of 131421405420303 is 303024504124131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131421405420303 - 2⁴ = 131421405420287 is a prime.

It is a super-2 number, since 2×131421405420303² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131421405420313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21903567570048 + ... + 21903567570053.

It is an arithmetic number, because the mean of its divisors is an integer number (43807135140102).

Almost surely, 2^{131421405420303} is an apocalyptic number.

131421405420303 is a deficient number, since it is larger than the sum of its proper divisors (43807135140105).

131421405420303 is an equidigital number, since it uses as much as digits as its factorization.

131421405420303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43807135140104.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 131421405420303 its reverse (303024504124131), we get a palindrome (434445909544434).

The spelling of 131421405420303 in words is "one hundred thirty-one trillion, four hundred twenty-one billion, four hundred five million, four hundred twenty thousand, three hundred three".