131421445412045 has 4 divisors (see below), whose sum is σ = 157705734494460. Its totient is φ = 105137156329632.

The previous prime is 131421445412041. The next prime is 131421445412113. The reversal of 131421445412045 is 540214544124131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 91442305127209 + 39979140284836 = 9562547^2 + 6322906^2 .

It is a cyclic number.

It is not a de Polignac number, because 131421445412045 - 2² = 131421445412041 is a prime.

It is a super-2 number, since 2×131421445412045² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131421445411993 and 131421445412011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131421445412041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13142144541200 + ... + 13142144541209.

It is an arithmetic number, because the mean of its divisors is an integer number (39426433623615).

Almost surely, 2^{131421445412045} is an apocalyptic number.

It is an amenable number.

131421445412045 is a deficient number, since it is larger than the sum of its proper divisors (26284289082415).

131421445412045 is an equidigital number, since it uses as much as digits as its factorization.

131421445412045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26284289082414.

The product of its (nonzero) digits is 307200, while the sum is 41.

Adding to 131421445412045 its reverse (540214544124131), we get a palindrome (671635989536176).

The spelling of 131421445412045 in words is "one hundred thirty-one trillion, four hundred twenty-one billion, four hundred forty-five million, four hundred twelve thousand, forty-five".