Base | Representation |
---|---|
bin | 10011000111111101011… |
… | …100011001101001110011 |
3 | 11122122020001100021021221 |
4 | 103013331130121221303 |
5 | 133013004034343120 |
6 | 2443424253325511 |
7 | 163643345041201 |
oct | 23077534315163 |
9 | 4578201307257 |
10 | 1314217106035 |
11 | 4673a13273a9 |
12 | 192854796897 |
13 | 96c1269c712 |
14 | 47873818071 |
15 | 242bc1410aa |
hex | 131fd719a73 |
1314217106035 has 12 divisors (see below), whose sum is σ = 1599585524784. Its totient is φ = 1036565584880.
The previous prime is 1314217106021. The next prime is 1314217106123. The reversal of 1314217106035 is 5306017124131.
It is not a de Polignac number, because 1314217106035 - 27 = 1314217105907 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 26045359 + ... + 26095768.
It is an arithmetic number, because the mean of its divisors is an integer number (133298793732).
Almost surely, 21314217106035 is an apocalyptic number.
1314217106035 is a deficient number, since it is larger than the sum of its proper divisors (285368418749).
1314217106035 is an frugal number, since it uses more digits than its factorization.
1314217106035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52141274 (or 52141203 counting only the distinct ones).
The product of its (nonzero) digits is 15120, while the sum is 34.
The spelling of 1314217106035 in words is "one trillion, three hundred fourteen billion, two hundred seventeen million, one hundred six thousand, thirty-five".
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