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13142201322211 = 131010938563247
BaseRepresentation
bin1011111100111110100000…
…1111011100101011100011
31201112101022121101011101221
42333033220033130223203
53210310212014302321
643541235520235511
72524331000034613
oct277175017345343
951471277334357
1013142201322211
114207638036895
12158306876bb97
137443c5622820
1433612bb56a43
1517bcd3786e41
hexbf3e83dcae3

13142201322211 has 4 divisors (see below), whose sum is σ = 14153139885472. Its totient is φ = 12131262758952.

The previous prime is 13142201322209. The next prime is 13142201322233. The reversal of 13142201322211 is 11222310224131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13142201322211 - 21 = 13142201322209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13142201322241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505469281611 + ... + 505469281636.

It is an arithmetic number, because the mean of its divisors is an integer number (3538284971368).

Almost surely, 213142201322211 is an apocalyptic number.

13142201322211 is a deficient number, since it is larger than the sum of its proper divisors (1010938563261).

13142201322211 is a wasteful number, since it uses less digits than its factorization.

13142201322211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1010938563260.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13142201322211 its reverse (11222310224131), we get a palindrome (24364511546342).

The spelling of 13142201322211 in words is "thirteen trillion, one hundred forty-two billion, two hundred one million, three hundred twenty-two thousand, two hundred eleven".

Divisors: 1 13 1010938563247 13142201322211