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13142225011103 = 24287354111511
BaseRepresentation
bin1011111100111110100110…
…1001110100000110011111
31201112101101020221200110022
42333033221221310012133
53210310234100323403
643541242124102355
72524331405266466
oct277175151640637
951471336850408
1013142225011103
11420764a446691
1215830746949bb
137443ca4c8016
14336130d619dd
1517bcd58b5d38
hexbf3e9a7419f

13142225011103 has 4 divisors (see below), whose sum is σ = 13142279365488. Its totient is φ = 13142170656720.

The previous prime is 13142225011087. The next prime is 13142225011151. The reversal of 13142225011103 is 30111052224131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13142225011103 - 24 = 13142225011087 is a prime.

It is a super-2 number, since 2×131422250111032 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13142225011193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26812883 + ... + 27298628.

It is an arithmetic number, because the mean of its divisors is an integer number (3285569841372).

Almost surely, 213142225011103 is an apocalyptic number.

13142225011103 is a deficient number, since it is larger than the sum of its proper divisors (54354385).

13142225011103 is an equidigital number, since it uses as much as digits as its factorization.

13142225011103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54354384.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 13142225011103 its reverse (30111052224131), we get a palindrome (43253277235234).

The spelling of 13142225011103 in words is "thirteen trillion, one hundred forty-two billion, two hundred twenty-five million, eleven thousand, one hundred three".

Divisors: 1 242873 54111511 13142225011103