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13142231203045 = 571072335017469
BaseRepresentation
bin1011111100111110101000…
…0001011011110011100101
31201112101101200121021012111
42333033222001123303211
53210310242141444140
643541242504521021
72524331512026010
oct277175201336345
951471350537174
1013142231203045
11420765299579a
121583076780171
137443cb8854a9
14336131ad4377
1517bcd61da7ea
hexbf3ea05bce5

13142231203045 has 16 divisors (see below), whose sum is σ = 18025312717440. Its totient is φ = 9010975005504.

The previous prime is 13142231203027. The next prime is 13142231203051. The reversal of 13142231203045 is 54030213224131.

It is a cyclic number.

It is not a de Polignac number, because 13142231203045 - 213 = 13142231194853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13142231202998 and 13142231203016.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17133430 + ... + 17884039.

It is an arithmetic number, because the mean of its divisors is an integer number (1126582044840).

Almost surely, 213142231203045 is an apocalyptic number.

It is an amenable number.

13142231203045 is a deficient number, since it is larger than the sum of its proper divisors (4883081514395).

13142231203045 is a wasteful number, since it uses less digits than its factorization.

13142231203045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35028204.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 13142231203045 its reverse (54030213224131), we get a palindrome (67172444427176).

The spelling of 13142231203045 in words is "thirteen trillion, one hundred forty-two billion, two hundred thirty-one million, two hundred three thousand, forty-five".

Divisors: 1 5 7 35 10723 53615 75061 375305 35017469 175087345 245122283 1225611415 375492320087 1877461600435 2628446240609 13142231203045