Base | Representation |
---|---|
bin | 1011111100111110101000… |
… | …0001011011110011100101 |
3 | 1201112101101200121021012111 |
4 | 2333033222001123303211 |
5 | 3210310242141444140 |
6 | 43541242504521021 |
7 | 2524331512026010 |
oct | 277175201336345 |
9 | 51471350537174 |
10 | 13142231203045 |
11 | 420765299579a |
12 | 1583076780171 |
13 | 7443cb8854a9 |
14 | 336131ad4377 |
15 | 17bcd61da7ea |
hex | bf3ea05bce5 |
13142231203045 has 16 divisors (see below), whose sum is σ = 18025312717440. Its totient is φ = 9010975005504.
The previous prime is 13142231203027. The next prime is 13142231203051. The reversal of 13142231203045 is 54030213224131.
It is a cyclic number.
It is not a de Polignac number, because 13142231203045 - 213 = 13142231194853 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13142231202998 and 13142231203016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17133430 + ... + 17884039.
It is an arithmetic number, because the mean of its divisors is an integer number (1126582044840).
Almost surely, 213142231203045 is an apocalyptic number.
It is an amenable number.
13142231203045 is a deficient number, since it is larger than the sum of its proper divisors (4883081514395).
13142231203045 is a wasteful number, since it uses less digits than its factorization.
13142231203045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35028204.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 13142231203045 its reverse (54030213224131), we get a palindrome (67172444427176).
The spelling of 13142231203045 in words is "thirteen trillion, one hundred forty-two billion, two hundred thirty-one million, two hundred three thousand, forty-five".
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