Base | Representation |
---|---|
bin | 1011111100111110101000… |
… | …0001011110000001100111 |
3 | 1201112101101200121201200011 |
4 | 2333033222001132001213 |
5 | 3210310242142242020 |
6 | 43541242505031051 |
7 | 2524331512064344 |
oct | 277175201360147 |
9 | 51471350551604 |
10 | 13142231212135 |
11 | 42076529a1603 |
12 | 1583076785487 |
13 | 7443cb88967c |
14 | 336131ad77cb |
15 | 17bcd61dd35a |
hex | bf3ea05e067 |
13142231212135 has 8 divisors (see below), whose sum is σ = 15770820698640. Its totient is φ = 10513689473664.
The previous prime is 13142231212111. The next prime is 13142231212141. The reversal of 13142231212135 is 53121213224131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13142231212135 - 213 = 13142231203943 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13142231212097 and 13142231212106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11328657 + ... + 12434746.
It is an arithmetic number, because the mean of its divisors is an integer number (1971352587330).
Almost surely, 213142231212135 is an apocalyptic number.
13142231212135 is a deficient number, since it is larger than the sum of its proper divisors (2628589486505).
13142231212135 is a wasteful number, since it uses less digits than its factorization.
13142231212135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23874017.
The product of its digits is 8640, while the sum is 31.
Adding to 13142231212135 its reverse (53121213224131), we get a palindrome (66263444436266).
The spelling of 13142231212135 in words is "thirteen trillion, one hundred forty-two billion, two hundred thirty-one million, two hundred twelve thousand, one hundred thirty-five".
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