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13142231212135 = 511060923763403
BaseRepresentation
bin1011111100111110101000…
…0001011110000001100111
31201112101101200121201200011
42333033222001132001213
53210310242142242020
643541242505031051
72524331512064344
oct277175201360147
951471350551604
1013142231212135
1142076529a1603
121583076785487
137443cb88967c
14336131ad77cb
1517bcd61dd35a
hexbf3ea05e067

13142231212135 has 8 divisors (see below), whose sum is σ = 15770820698640. Its totient is φ = 10513689473664.

The previous prime is 13142231212111. The next prime is 13142231212141. The reversal of 13142231212135 is 53121213224131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13142231212135 - 213 = 13142231203943 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13142231212097 and 13142231212106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11328657 + ... + 12434746.

It is an arithmetic number, because the mean of its divisors is an integer number (1971352587330).

Almost surely, 213142231212135 is an apocalyptic number.

13142231212135 is a deficient number, since it is larger than the sum of its proper divisors (2628589486505).

13142231212135 is a wasteful number, since it uses less digits than its factorization.

13142231212135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23874017.

The product of its digits is 8640, while the sum is 31.

Adding to 13142231212135 its reverse (53121213224131), we get a palindrome (66263444436266).

The spelling of 13142231212135 in words is "thirteen trillion, one hundred forty-two billion, two hundred thirty-one million, two hundred twelve thousand, one hundred thirty-five".

Divisors: 1 5 110609 553045 23763403 118817015 2628446242427 13142231212135