131422414020043 has 8 divisors (see below), whose sum is σ = 131856159370320. Its totient is φ = 130989240518400.

The previous prime is 131422414020011. The next prime is 131422414020091. The reversal of 131422414020043 is 340020414224131.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131422414020043 - 2⁵ = 131422414020011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131422414019987 and 131422414020014.

It is not an unprimeable number, because it can be changed into a prime (131422414020643) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 142501758 + ... + 143421043.

It is an arithmetic number, because the mean of its divisors is an integer number (16482019921290).

Almost surely, 2^{131422414020043} is an apocalyptic number.

131422414020043 is a deficient number, since it is larger than the sum of its proper divisors (433745350277).

131422414020043 is a wasteful number, since it uses less digits than its factorization.

131422414020043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 285924317.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 131422414020043 its reverse (340020414224131), we get a palindrome (471442828244174).

The spelling of 131422414020043 in words is "one hundred thirty-one trillion, four hundred twenty-two billion, four hundred fourteen million, twenty thousand, forty-three".