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1314230433035 = 51324907811777
BaseRepresentation
bin10011000111111110001…
…111001111010100001011
311122122020222102100111112
4103013332033033110023
5133013020442324120
62443425451120535
7163643566235342
oct23077617172413
94578228370445
101314230433035
114673a88aa153
1219285914314b
1396c15387710
14478754c6b59
15242bd3c4bc5
hex131fe3cf50b

1314230433035 has 16 divisors (see below), whose sum is σ = 1698460379616. Its totient is φ = 970468466688.

The previous prime is 1314230433023. The next prime is 1314230433077. The reversal of 1314230433035 is 5303340324131.

It is a cyclic number.

It is not a de Polignac number, because 1314230433035 - 26 = 1314230432971 is a prime.

It is a super-2 number, since 2×13142304330352 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1314230432992 and 1314230433010.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1213067 + ... + 2024843.

It is an arithmetic number, because the mean of its divisors is an integer number (106153773726).

Almost surely, 21314230433035 is an apocalyptic number.

1314230433035 is a deficient number, since it is larger than the sum of its proper divisors (384229946581).

1314230433035 is a wasteful number, since it uses less digits than its factorization.

1314230433035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 836702.

The product of its (nonzero) digits is 38880, while the sum is 32.

Adding to 1314230433035 its reverse (5303340324131), we get a palindrome (6617570757166).

The spelling of 1314230433035 in words is "one trillion, three hundred fourteen billion, two hundred thirty million, four hundred thirty-three thousand, thirty-five".

Divisors: 1 5 13 65 24907 124535 323791 811777 1618955 4058885 10553101 52765505 20218929739 101094648695 262846086607 1314230433035