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13142330250335 = 5111318380881469
BaseRepresentation
bin1011111100111110111111…
…1011010001010001011111
31201112101122120222101112122
42333033233323101101133
53210310443021002320
643541300403453155
72524334123642426
oct277175773212137
951471576871478
1013142330250335
1142076a3896460
1215830a39871bb
13744416254460
14336140d182bd
1517bcdec52d25
hexbf3efed145f

13142330250335 has 16 divisors (see below), whose sum is σ = 18527928521760. Its totient is φ = 8822823104640.

The previous prime is 13142330250293. The next prime is 13142330250353. The reversal of 13142330250335 is 53305203324131.

It is not a de Polignac number, because 13142330250335 - 214 = 13142330233951 is a prime.

It is a super-2 number, since 2×131423302503352 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13142330250295 and 13142330250304.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9190440020 + ... + 9190441449.

It is an arithmetic number, because the mean of its divisors is an integer number (1157995532610).

Almost surely, 213142330250335 is an apocalyptic number.

13142330250335 is a deficient number, since it is larger than the sum of its proper divisors (5385598271425).

13142330250335 is a wasteful number, since it uses less digits than its factorization.

13142330250335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18380881498.

The product of its (nonzero) digits is 97200, while the sum is 35.

Adding to 13142330250335 its reverse (53305203324131), we get a palindrome (66447533574466).

The spelling of 13142330250335 in words is "thirteen trillion, one hundred forty-two billion, three hundred thirty million, two hundred fifty thousand, three hundred thirty-five".

Divisors: 1 5 11 13 55 65 143 715 18380881469 91904407345 202189696159 238951459097 1010948480795 1194757295485 2628466050067 13142330250335