Base | Representation |
---|---|
bin | 1011111100111111000100… |
… | …0111110001010001011001 |
3 | 1201112101200222201020110202 |
4 | 2333033301013301101121 |
5 | 3210311013134214340 |
6 | 43541302401351545 |
7 | 2524334456255063 |
oct | 277176107612131 |
9 | 51471628636422 |
10 | 13142350304345 |
11 | 4207704143319 |
12 | 15830aa6385b5 |
13 | 74441a456332 |
14 | 336143858733 |
15 | 17bce18b4c15 |
hex | bf3f11f1459 |
13142350304345 has 16 divisors (see below), whose sum is σ = 16051407310848. Its totient is φ = 10327296450240.
The previous prime is 13142350304257. The next prime is 13142350304411. The reversal of 13142350304345 is 54340305324131.
It is not a de Polignac number, because 13142350304345 - 220 = 13142349255769 is a prime.
It is a super-2 number, since 2×131423503043452 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13142350304299 and 13142350304308.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29413529 + ... + 29856998.
It is an arithmetic number, because the mean of its divisors is an integer number (1003212956928).
Almost surely, 213142350304345 is an apocalyptic number.
It is an amenable number.
13142350304345 is a deficient number, since it is larger than the sum of its proper divisors (2909057006503).
13142350304345 is an equidigital number, since it uses as much as digits as its factorization.
13142350304345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 59271320.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 13142350304345 its reverse (54340305324131), we get a palindrome (67482655628476).
The spelling of 13142350304345 in words is "thirteen trillion, one hundred forty-two billion, three hundred fifty million, three hundred four thousand, three hundred forty-five".
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