13142413025041 has 4 divisors (see below), whose sum is σ = 13146949587492. Its totient is φ = 13137876462592.

The previous prime is 13142413025009. The next prime is 13142413025069. The reversal of 13142413025041 is 14052031424131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 715201724416 + 12427211300625 = 845696^2 + 3525225^2 .

It is a cyclic number.

It is not a de Polignac number, because 13142413025041 - 2⁵ = 13142413025009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13142413024994 and 13142413025012.

It is not an unprimeable number, because it can be changed into a prime (13142413025641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2268276880 + ... + 2268282673.

It is an arithmetic number, because the mean of its divisors is an integer number (3286737396873).

Almost surely, 2^{13142413025041} is an apocalyptic number.

It is an amenable number.

13142413025041 is a deficient number, since it is larger than the sum of its proper divisors (4536562451).

13142413025041 is an equidigital number, since it uses as much as digits as its factorization.

13142413025041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4536562450.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 13142413025041 its reverse (14052031424131), we get a palindrome (27194444449172).

The spelling of 13142413025041 in words is "thirteen trillion, one hundred forty-two billion, four hundred thirteen million, twenty-five thousand, forty-one".