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13142413415543 = 25915950711777
BaseRepresentation
bin1011111100111111010011…
…1000100001010001110111
31201112101212101110121202112
42333033310320201101313
53210311130313244133
643541312534201235
72524336153560536
oct277176470412167
951471771417675
1013142413415543
114207736829735
1215831077b321b
1374442a552439
1433614bda631d
1517bce71ce648
hexbf3f4e21477

13142413415543 has 4 divisors (see below), whose sum is σ = 13142464386480. Its totient is φ = 13142362444608.

The previous prime is 13142413415519. The next prime is 13142413415611. The reversal of 13142413415543 is 34551431424131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13142413415543 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13142413415543.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13142613415543) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25096730 + ... + 25615047.

It is an arithmetic number, because the mean of its divisors is an integer number (3285616096620).

Almost surely, 213142413415543 is an apocalyptic number.

13142413415543 is a deficient number, since it is larger than the sum of its proper divisors (50970937).

13142413415543 is an equidigital number, since it uses as much as digits as its factorization.

13142413415543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50970936.

The product of its digits is 345600, while the sum is 41.

Adding to 13142413415543 its reverse (34551431424131), we get a palindrome (47693844839674).

The spelling of 13142413415543 in words is "thirteen trillion, one hundred forty-two billion, four hundred thirteen million, four hundred fifteen thousand, five hundred forty-three".

Divisors: 1 259159 50711777 13142413415543