1314244031 has 4 divisors (see below), whose sum is σ = 1319743200. Its totient is φ = 1308744864.

The previous prime is 1314243991. The next prime is 1314244067. The reversal of 1314244031 is 1304424131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1304424131 = 10223 ⋅127597.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1314244031 is a prime.

It is a super-2 number, since 2×1314244031² = 3454474746038257922, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1314243988 and 1314244006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314244091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2749226 + ... + 2749703.

It is an arithmetic number, because the mean of its divisors is an integer number (329935800).

Almost surely, 2^1314244031 is an apocalyptic number.

1314244031 is a deficient number, since it is larger than the sum of its proper divisors (5499169).

1314244031 is an equidigital number, since it uses as much as digits as its factorization.

1314244031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5499168.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 1314244031 is about 36252.5037893936. The cubic root of 1314244031 is about 1095.3645238002.

Adding to 1314244031 its reverse (1304424131), we get a palindrome (2618668162).

The spelling of 1314244031 in words is "one billion, three hundred fourteen million, two hundred forty-four thousand, thirty-one".