Base | Representation |
---|---|
bin | 10011001000000010100… |
… | …000011101001001110001 |
3 | 11122122102222012010101211 |
4 | 103020002200131021301 |
5 | 133013142311230100 |
6 | 2443440530200121 |
7 | 163645426065661 |
oct | 23100240351161 |
9 | 4578388163354 |
10 | 1314302055025 |
11 | 467435278883 |
12 | 192879123041 |
13 | 96c271735ab |
14 | 47880c0c1a1 |
15 | 242c48211ba |
hex | 1320281d271 |
1314302055025 has 6 divisors (see below), whose sum is σ = 1629734548262. Its totient is φ = 1051441644000.
The previous prime is 1314302055023. The next prime is 1314302055029. The reversal of 1314302055025 is 5205502034131.
It can be written as a sum of positive squares in 3 ways, for example, as 343428816784 + 970873238241 = 586028^2 + 985329^2 .
It is not a de Polignac number, because 1314302055025 - 21 = 1314302055023 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1314302055023) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 26286041076 + ... + 26286041125.
Almost surely, 21314302055025 is an apocalyptic number.
It is an amenable number.
1314302055025 is a deficient number, since it is larger than the sum of its proper divisors (315432493237).
1314302055025 is an equidigital number, since it uses as much as digits as its factorization.
1314302055025 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52572082211 (or 52572082206 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 1314302055025 its reverse (5205502034131), we get a palindrome (6519804089156).
The spelling of 1314302055025 in words is "one trillion, three hundred fourteen billion, three hundred two million, fifty-five thousand, twenty-five".
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