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1314311031433 = 4111731965149
BaseRepresentation
bin10011001000000011000…
…010101100101010001001
311122122110121002011201101
4103020003002230222021
5133013202111001213
62443441450421401
7163645565303161
oct23100302545211
94578417064641
101314311031433
1146743a3499a4
12192880131861
1396c28c9728a
14478820a75a1
15242c54e5bdd
hex132030aca89

1314311031433 has 4 divisors (see below), whose sum is σ = 1314343037700. Its totient is φ = 1314279025168.

The previous prime is 1314311031419. The next prime is 1314311031521. The reversal of 1314311031433 is 3341301134131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1107602590329 + 206708441104 = 1052427^2 + 454652^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314311031433 - 229 = 1313774160521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1314311031413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15941458 + ... + 16023691.

It is an arithmetic number, because the mean of its divisors is an integer number (328585759425).

Almost surely, 21314311031433 is an apocalyptic number.

It is an amenable number.

1314311031433 is a deficient number, since it is larger than the sum of its proper divisors (32006267).

1314311031433 is an equidigital number, since it uses as much as digits as its factorization.

1314311031433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32006266.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 1314311031433 its reverse (3341301134131), we get a palindrome (4655612165564).

The spelling of 1314311031433 in words is "one trillion, three hundred fourteen billion, three hundred eleven million, thirty-one thousand, four hundred thirty-three".

Divisors: 1 41117 31965149 1314311031433