131431225335 has 8 divisors (see below), whose sum is σ = 210289960560. Its totient is φ = 70096653504.

The previous prime is 131431225327. The next prime is 131431225379. The reversal of 131431225335 is 533522134131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131431225335 - 2³ = 131431225327 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131431225296 and 131431225305.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4381040830 + ... + 4381040859.

It is an arithmetic number, because the mean of its divisors is an integer number (26286245070).

Almost surely, 2^131431225335 is an apocalyptic number.

131431225335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131431225335 is a deficient number, since it is larger than the sum of its proper divisors (78858735225).

131431225335 is an equidigital number, since it uses as much as digits as its factorization.

131431225335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8762081697.

The product of its digits is 32400, while the sum is 33.

Adding to 131431225335 its reverse (533522134131), we get a palindrome (664953359466).

The spelling of 131431225335 in words is "one hundred thirty-one billion, four hundred thirty-one million, two hundred twenty-five thousand, three hundred thirty-five".