Base | Representation |
---|---|
bin | 11101111000100100110111… |
… | …110010001101100000110011 |
3 | 122020100200222102000021200021 |
4 | 131320210313302031200303 |
5 | 114211332124403244243 |
6 | 1143310401254504311 |
7 | 36453410256134020 |
oct | 3570446762154063 |
9 | 566320872007607 |
10 | 131431230134323 |
11 | 38972743007689 |
12 | 128a8305065097 |
13 | 5844bb1369782 |
14 | 246543c348547 |
15 | 102dc643216ed |
hex | 778937c8d833 |
131431230134323 has 8 divisors (see below), whose sum is σ = 150778249890048. Its totient is φ = 112226992812744.
The previous prime is 131431230134279. The next prime is 131431230134341. The reversal of 131431230134323 is 323431032134131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131431230134323 - 217 = 131431230003251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131431230134923) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35695606561 + ... + 35695610242.
It is an arithmetic number, because the mean of its divisors is an integer number (18847281236256).
Almost surely, 2131431230134323 is an apocalyptic number.
131431230134323 is a deficient number, since it is larger than the sum of its proper divisors (19347019755725).
131431230134323 is an equidigital number, since it uses as much as digits as its factorization.
131431230134323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71391217073.
The product of its (nonzero) digits is 46656, while the sum is 34.
Adding to 131431230134323 its reverse (323431032134131), we get a palindrome (454862262268454).
The spelling of 131431230134323 in words is "one hundred thirty-one trillion, four hundred thirty-one billion, two hundred thirty million, one hundred thirty-four thousand, three hundred twenty-three".
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