Base | Representation |
---|---|
bin | 111101001100111110… |
… | …1010101010100011010 |
3 | 110120020201111221110112 |
4 | 1322121331111110122 |
5 | 4123133043323114 |
6 | 140213512044322 |
7 | 12332002442432 |
oct | 1723175252432 |
9 | 416221457415 |
10 | 131432011034 |
11 | 50815a42225 |
12 | 215803936a2 |
13 | c51778073c |
14 | 650b7512c2 |
15 | 364392d13e |
hex | 1e99f5551a |
131432011034 has 4 divisors (see below), whose sum is σ = 197148016554. Its totient is φ = 65716005516.
The previous prime is 131432011027. The next prime is 131432011063. The reversal of 131432011034 is 430110234131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 129849960409 + 1582050625 = 360347^2 + 39775^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32858002757 + ... + 32858002760.
Almost surely, 2131432011034 is an apocalyptic number.
131432011034 is a deficient number, since it is larger than the sum of its proper divisors (65716005520).
131432011034 is an equidigital number, since it uses as much as digits as its factorization.
131432011034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65716005519.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 131432011034 its reverse (430110234131), we get a palindrome (561542245165).
The spelling of 131432011034 in words is "one hundred thirty-one billion, four hundred thirty-two million, eleven thousand, thirty-four".
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