Base | Representation |
---|---|
bin | 111101001100111110… |
… | …1110011010110001111 |
3 | 110120020201202012011222 |
4 | 1322121331303112033 |
5 | 4123133111242111 |
6 | 140213514433555 |
7 | 12332003464142 |
oct | 1723175632617 |
9 | 416221665158 |
10 | 131432134031 |
11 | 50816016680 |
12 | 215804328bb |
13 | c5177c4713 |
14 | 650b784059 |
15 | 36439547db |
hex | 1e99f7358f |
131432134031 has 4 divisors (see below), whose sum is σ = 143380509864. Its totient is φ = 119483758200.
The previous prime is 131432134027. The next prime is 131432134063. The reversal of 131432134031 is 130431234131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131432134031 - 22 = 131432134027 is a prime.
It is a super-2 number, since 2×1314321340312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131432134531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5974187900 + ... + 5974187921.
It is an arithmetic number, because the mean of its divisors is an integer number (35845127466).
Almost surely, 2131432134031 is an apocalyptic number.
131432134031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
131432134031 is a deficient number, since it is larger than the sum of its proper divisors (11948375833).
131432134031 is a wasteful number, since it uses less digits than its factorization.
131432134031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11948375832.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 131432134031 its reverse (130431234131), we get a palindrome (261863368162).
The spelling of 131432134031 in words is "one hundred thirty-one billion, four hundred thirty-two million, one hundred thirty-four thousand, thirty-one".
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