13143305154535 has 4 divisors (see below), whose sum is σ = 15771966185448. Its totient is φ = 10514644123624.

The previous prime is 13143305154521. The next prime is 13143305154541. The reversal of 13143305154535 is 53545150334131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13143305154535 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13143305154491 and 13143305154500.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1314330515449 + ... + 1314330515458.

It is an arithmetic number, because the mean of its divisors is an integer number (3942991546362).

Almost surely, 2^{13143305154535} is an apocalyptic number.

13143305154535 is a deficient number, since it is larger than the sum of its proper divisors (2628661030913).

13143305154535 is an equidigital number, since it uses as much as digits as its factorization.

13143305154535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2628661030912.

The product of its (nonzero) digits is 810000, while the sum is 43.

Adding to 13143305154535 its reverse (53545150334131), we get a palindrome (66688455488666).

The spelling of 13143305154535 in words is "thirteen trillion, one hundred forty-three billion, three hundred five million, one hundred fifty-four thousand, five hundred thirty-five".