13143311253353 has 4 divisors (see below), whose sum is σ = 13498535881860. Its totient is φ = 12788086624848.

The previous prime is 13143311253341. The next prime is 13143311253367. The reversal of 13143311253353 is 35335211334131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 11695216709929 + 1448094543424 = 3419827^2 + 1203368^2 .

It is a cyclic number.

It is not a de Polignac number, because 13143311253353 - 2⁴ = 13143311253337 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13143311252353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177612314198 + ... + 177612314271.

It is an arithmetic number, because the mean of its divisors is an integer number (3374633970465).

Almost surely, 2^{13143311253353} is an apocalyptic number.

It is an amenable number.

13143311253353 is a deficient number, since it is larger than the sum of its proper divisors (355224628507).

13143311253353 is an equidigital number, since it uses as much as digits as its factorization.

13143311253353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 355224628506.

The product of its digits is 145800, while the sum is 38.

Adding to 13143311253353 its reverse (35335211334131), we get a palindrome (48478522587484).

The spelling of 13143311253353 in words is "thirteen trillion, one hundred forty-three billion, three hundred eleven million, two hundred fifty-three thousand, three hundred fifty-three".