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131433211404103 = 759931345864871
BaseRepresentation
bin11101111000100110101101…
…111000001001111101000111
3122020100220002111010012212111
4131320212231320021331013
5114211400204104412403
61143311330032201451
736453510334505530
oct3570465570117507
9566326074105774
10131433211404103
113897356a420a24
12128a8778699287
13584513898665b
142465589529687
15102dd2d23456d
hex7789ade09f47

131433211404103 has 8 divisors (see below), whose sum is σ = 150460151385600. Its totient is φ = 112468963153560.

The previous prime is 131433211404091. The next prime is 131433211404113. The reversal of 131433211404103 is 301404112334131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131433211404103 - 25 = 131433211404071 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131433211404113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15672928243 + ... + 15672936628.

It is an arithmetic number, because the mean of its divisors is an integer number (18807518923200).

Almost surely, 2131433211404103 is an apocalyptic number.

131433211404103 is a deficient number, since it is larger than the sum of its proper divisors (19026939981497).

131433211404103 is an equidigital number, since it uses as much as digits as its factorization.

131433211404103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31345865477.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 131433211404103 its reverse (301404112334131), we get a palindrome (432837323738234).

The spelling of 131433211404103 in words is "one hundred thirty-one trillion, four hundred thirty-three billion, two hundred eleven million, four hundred four thousand, one hundred three".

Divisors: 1 7 599 4193 31345864871 219421054097 18776173057729 131433211404103