Base | Representation |
---|---|
bin | 11000011110110011… |
… | …10011010101110111 |
3 | 1020220222111001001122 |
4 | 30033121303111313 |
5 | 203404142332043 |
6 | 10012111014155 |
7 | 643463260634 |
oct | 141731632567 |
9 | 36828431048 |
10 | 13143324023 |
11 | 5635077965 |
12 | 266980a35b |
13 | 1315ca400b |
14 | 8c97d718b |
15 | 51dd13368 |
hex | 30f673577 |
13143324023 has 4 divisors (see below), whose sum is σ = 13144465488. Its totient is φ = 13142182560.
The previous prime is 13143323939. The next prime is 13143324041. The reversal of 13143324023 is 32042334131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13143324023 - 212 = 13143319927 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13143323983 and 13143324001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13143323023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 553283 + ... + 576548.
It is an arithmetic number, because the mean of its divisors is an integer number (3286116372).
Almost surely, 213143324023 is an apocalyptic number.
13143324023 is a deficient number, since it is larger than the sum of its proper divisors (1141465).
13143324023 is a wasteful number, since it uses less digits than its factorization.
13143324023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1141464.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 13143324023 its reverse (32042334131), we get a palindrome (45185658154).
The spelling of 13143324023 in words is "thirteen billion, one hundred forty-three million, three hundred twenty-four thousand, twenty-three".
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