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13143351224131 = 25795096297489
BaseRepresentation
bin1011111101000010110011…
…0001111110011101000011
31201112111021202010020021221
42333100230301332131003
53210320040403133011
643541545554455511
72524401332036422
oct277205461763503
951474252106257
1013143351224131
114208078135157
121583329894597
1374454992606b
143361da7652b9
1517bd4e6c8971
hexbf42cc7e743

13143351224131 has 4 divisors (see below), whose sum is σ = 13148447524200. Its totient is φ = 13138254924064.

The previous prime is 13143351224123. The next prime is 13143351224183. The reversal of 13143351224131 is 13142215334131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13143351224131 - 23 = 13143351224123 is a prime.

It is a super-2 number, since 2×131433512241312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13143351227131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2548146166 + ... + 2548151323.

It is an arithmetic number, because the mean of its divisors is an integer number (3287111881050).

Almost surely, 213143351224131 is an apocalyptic number.

13143351224131 is a deficient number, since it is larger than the sum of its proper divisors (5096300069).

13143351224131 is an equidigital number, since it uses as much as digits as its factorization.

13143351224131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5096300068.

The product of its digits is 25920, while the sum is 34.

Adding to 13143351224131 its reverse (13142215334131), we get a palindrome (26285566558262).

The spelling of 13143351224131 in words is "thirteen trillion, one hundred forty-three billion, three hundred fifty-one million, two hundred twenty-four thousand, one hundred thirty-one".

Divisors: 1 2579 5096297489 13143351224131