13143412033 has 4 divisors (see below), whose sum is σ = 13148406468. Its totient is φ = 13138417600.

The previous prime is 13143411971. The next prime is 13143412049. The reversal of 13143412033 is 33021434131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4769697969 + 8373714064 = 69063^2 + 91508^2 .

It is a cyclic number.

It is not a de Polignac number, because 13143412033 - 2²⁵ = 13109857601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13143411989 and 13143412007.

It is not an unprimeable number, because it can be changed into a prime (13143413033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2493268 + ... + 2498533.

It is an arithmetic number, because the mean of its divisors is an integer number (3287101617).

Almost surely, 2^13143412033 is an apocalyptic number.

It is an amenable number.

13143412033 is a deficient number, since it is larger than the sum of its proper divisors (4994435).

13143412033 is an equidigital number, since it uses as much as digits as its factorization.

13143412033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4994434.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13143412033 its reverse (33021434131), we get a palindrome (46164846164).

The spelling of 13143412033 in words is "thirteen billion, one hundred forty-three million, four hundred twelve thousand, thirty-three".