Base | Representation |
---|---|
bin | 10011001000000100111… |
… | …001010011101001000111 |
3 | 11122122112202120211211202 |
4 | 103020010321103221013 |
5 | 133013233040432403 |
6 | 2443444521053115 |
7 | 163646423502311 |
oct | 23100471235107 |
9 | 4578482524752 |
10 | 1314342124103 |
11 | 467455956318 |
12 | 19288a62719b |
13 | 96c325626c8 |
14 | 4788627c7b1 |
15 | 242c80d8688 |
hex | 13204e53a47 |
1314342124103 has 4 divisors (see below), whose sum is σ = 1325973470448. Its totient is φ = 1302710777760.
The previous prime is 1314342124093. The next prime is 1314342124127. The reversal of 1314342124103 is 3014212434131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1314342124103 - 28 = 1314342123847 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1314342126103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5815673003 + ... + 5815673228.
It is an arithmetic number, because the mean of its divisors is an integer number (331493367612).
Almost surely, 21314342124103 is an apocalyptic number.
1314342124103 is a deficient number, since it is larger than the sum of its proper divisors (11631346345).
1314342124103 is a wasteful number, since it uses less digits than its factorization.
1314342124103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11631346344.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1314342124103 its reverse (3014212434131), we get a palindrome (4328554558234).
The spelling of 1314342124103 in words is "one trillion, three hundred fourteen billion, three hundred forty-two million, one hundred twenty-four thousand, one hundred three".
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