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1314342124103 = 11311631346231
BaseRepresentation
bin10011001000000100111…
…001010011101001000111
311122122112202120211211202
4103020010321103221013
5133013233040432403
62443444521053115
7163646423502311
oct23100471235107
94578482524752
101314342124103
11467455956318
1219288a62719b
1396c325626c8
144788627c7b1
15242c80d8688
hex13204e53a47

1314342124103 has 4 divisors (see below), whose sum is σ = 1325973470448. Its totient is φ = 1302710777760.

The previous prime is 1314342124093. The next prime is 1314342124127. The reversal of 1314342124103 is 3014212434131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314342124103 - 28 = 1314342123847 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314342126103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5815673003 + ... + 5815673228.

It is an arithmetic number, because the mean of its divisors is an integer number (331493367612).

Almost surely, 21314342124103 is an apocalyptic number.

1314342124103 is a deficient number, since it is larger than the sum of its proper divisors (11631346345).

1314342124103 is a wasteful number, since it uses less digits than its factorization.

1314342124103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11631346344.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1314342124103 its reverse (3014212434131), we get a palindrome (4328554558234).

The spelling of 1314342124103 in words is "one trillion, three hundred fourteen billion, three hundred forty-two million, one hundred twenty-four thousand, one hundred three".

Divisors: 1 113 11631346231 1314342124103