Base | Representation |
---|---|
bin | 11101111000101000100101… |
… | …110101101011100011011111 |
3 | 122020101002021202012202112000 |
4 | 131320220211311223203133 |
5 | 114211413314322134330 |
6 | 1143312301445413343 |
7 | 36453611243460102 |
oct | 3570504565534337 |
9 | 566332252182460 |
10 | 131435224021215 |
11 | 389744024a5a54 |
12 | 128a903a70a253 |
13 | 584539992a85a |
14 | 24656da94a739 |
15 | 102dde9c8a560 |
hex | 778a25d6b8df |
131435224021215 has 16 divisors (see below), whose sum is σ = 233662620482400. Its totient is φ = 70098786144576.
The previous prime is 131435224021193. The next prime is 131435224021253. The reversal of 131435224021215 is 512120422534131.
131435224021215 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 3 + 522 + 4 + 0 + 2 + 121 + 5 = 666.
It is not a de Polignac number, because 131435224021215 - 224 = 131435207243999 is a prime.
It is a super-2 number, since 2×1314352240212152 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131435224021215.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 486797125870 + ... + 486797126139.
It is an arithmetic number, because the mean of its divisors is an integer number (14603913780150).
Almost surely, 2131435224021215 is an apocalyptic number.
131435224021215 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131435224021215 is a deficient number, since it is larger than the sum of its proper divisors (102227396461185).
131435224021215 is an equidigital number, since it uses as much as digits as its factorization.
131435224021215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 973594252023 (or 973594252017 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 36.
Adding to 131435224021215 its reverse (512120422534131), we get a palindrome (643555646555346).
The spelling of 131435224021215 in words is "one hundred thirty-one trillion, four hundred thirty-five billion, two hundred twenty-four million, twenty-one thousand, two hundred fifteen".
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