Base | Representation |
---|---|
bin | 100111001011000… |
… | …0010011100110111 |
3 | 10101121021102220112 |
4 | 1032112002130313 |
5 | 10142441300210 |
6 | 334232053235 |
7 | 44400134063 |
oct | 11626023467 |
9 | 3347242815 |
10 | 1314400055 |
11 | 614a43241 |
12 | 30823421b |
13 | 17c40a517 |
14 | c67ccaa3 |
15 | 7a5d6d05 |
hex | 4e582737 |
1314400055 has 4 divisors (see below), whose sum is σ = 1577280072. Its totient is φ = 1051520040.
The previous prime is 1314400027. The next prime is 1314400081. The reversal of 1314400055 is 5500044131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5500044131 = 11923 ⋅461297.
It is a de Polignac number, because none of the positive numbers 2k-1314400055 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1314400055.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131440001 + ... + 131440010.
It is an arithmetic number, because the mean of its divisors is an integer number (394320018).
Almost surely, 21314400055 is an apocalyptic number.
1314400055 is a deficient number, since it is larger than the sum of its proper divisors (262880017).
1314400055 is an equidigital number, since it uses as much as digits as its factorization.
1314400055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 262880016.
The product of its (nonzero) digits is 1200, while the sum is 23.
The square root of 1314400055 is about 36254.6556320702. The cubic root of 1314400055 is about 1095.4078684627.
Adding to 1314400055 its reverse (5500044131), we get a palindrome (6814444186).
The spelling of 1314400055 in words is "one billion, three hundred fourteen million, four hundred thousand, fifty-five".
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