Base | Representation |
---|---|
bin | 1011111101000101001110… |
… | …1110001110101100111111 |
3 | 1201112112222021110210202021 |
4 | 2333101103232032230333 |
5 | 3210322410131203120 |
6 | 43542134453541011 |
7 | 2524423454201032 |
oct | 277212356165477 |
9 | 51475867423667 |
10 | 13144004553535 |
11 | 42083829a8209 |
12 | 1583490644767 |
13 | 7446220a45cb |
14 | 33625d431019 |
15 | 17bd8bc2caaa |
hex | bf453b8eb3f |
13144004553535 has 8 divisors (see below), whose sum is σ = 15962839265520. Its totient is φ = 10388514441984.
The previous prime is 13144004553529. The next prime is 13144004553583. The reversal of 13144004553535 is 53535540044131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13144004553535 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13144004553491 and 13144004553500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15836149650 + ... + 15836150479.
It is an arithmetic number, because the mean of its divisors is an integer number (1995354908190).
Almost surely, 213144004553535 is an apocalyptic number.
13144004553535 is a deficient number, since it is larger than the sum of its proper divisors (2818834711985).
13144004553535 is an equidigital number, since it uses as much as digits as its factorization.
13144004553535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31672300217.
The product of its (nonzero) digits is 1080000, while the sum is 43.
Adding to 13144004553535 its reverse (53535540044131), we get a palindrome (66679544597666).
The spelling of 13144004553535 in words is "thirteen trillion, one hundred forty-four billion, four million, five hundred fifty-three thousand, five hundred thirty-five".
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