131440254032132 has 6 divisors (see below), whose sum is σ = 230020444556238. Its totient is φ = 65720127016064.

The previous prime is 131440254032123. The next prime is 131440254032149. The reversal of 131440254032132 is 231230452044131.

It can be written as a sum of positive squares in only one way, i.e., 82231235604736 + 49209018427396 = 9068144^2 + 7014914^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131440254032092 and 131440254032101.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16430031754013 + ... + 16430031754020.

It is an arithmetic number, because the mean of its divisors is an integer number (38336740759373).

Almost surely, 2^{131440254032132} is an apocalyptic number.

It is an amenable number.

131440254032132 is a deficient number, since it is larger than the sum of its proper divisors (98580190524106).

131440254032132 is a wasteful number, since it uses less digits than its factorization.

131440254032132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32860063508037 (or 32860063508035 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 35.

The spelling of 131440254032132 in words is "one hundred thirty-one trillion, four hundred forty billion, two hundred fifty-four million, thirty-two thousand, one hundred thirty-two".