Base | Representation |
---|---|
bin | 10011001000001000100… |
… | …110000111001100010011 |
3 | 11122122201002101200122210 |
4 | 103020020212013030103 |
5 | 133013344433414420 |
6 | 2443455015403203 |
7 | 163651106240226 |
oct | 23101046071423 |
9 | 4578632350583 |
10 | 1314404201235 |
11 | 4674879a5834 |
12 | 1928a7383503 |
13 | 96c42388c38 |
14 | 478905db5bd |
15 | 242cd79b9e0 |
hex | 13208987313 |
1314404201235 has 8 divisors (see below), whose sum is σ = 2103046722000. Its totient is φ = 701015573984.
The previous prime is 1314404201203. The next prime is 1314404201249. The reversal of 1314404201235 is 5321024044131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1314404201235 - 25 = 1314404201203 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43813473360 + ... + 43813473389.
It is an arithmetic number, because the mean of its divisors is an integer number (262880840250).
Almost surely, 21314404201235 is an apocalyptic number.
1314404201235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1314404201235 is a deficient number, since it is larger than the sum of its proper divisors (788642520765).
1314404201235 is an equidigital number, since it uses as much as digits as its factorization.
1314404201235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87626946757.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 1314404201235 its reverse (5321024044131), we get a palindrome (6635428245366).
The spelling of 1314404201235 in words is "one trillion, three hundred fourteen billion, four hundred four million, two hundred one thousand, two hundred thirty-five".
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