Base | Representation |
---|---|
bin | 11101111000101110001010… |
… | …111100010111100011110011 |
3 | 122020101122202021202020020011 |
4 | 131320232022330113203303 |
5 | 114212013102100143220 |
6 | 1143315132150155351 |
7 | 36454212563134402 |
oct | 3570561274274363 |
9 | 566348667666204 |
10 | 131441215240435 |
11 | 389769a73796a1 |
12 | 128aa231052b57 |
13 | 5845b12c40999 |
14 | 2465b08511639 |
15 | 102e14ac3b65a |
hex | 778b8af178f3 |
131441215240435 has 128 divisors (see below), whose sum is σ = 172469139840000. Its totient is φ = 95845574246400.
The previous prime is 131441215240409. The next prime is 131441215240477. The reversal of 131441215240435 is 534042512144131.
It is not a de Polignac number, because 131441215240435 - 25 = 131441215240403 is a prime.
It is a super-2 number, since 2×1314412152404352 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 77363869216 + ... + 77363870914.
It is an arithmetic number, because the mean of its divisors is an integer number (1347415155000).
Almost surely, 2131441215240435 is an apocalyptic number.
131441215240435 is a deficient number, since it is larger than the sum of its proper divisors (41027924599565).
131441215240435 is a wasteful number, since it uses less digits than its factorization.
131441215240435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2837.
The product of its (nonzero) digits is 230400, while the sum is 40.
Adding to 131441215240435 its reverse (534042512144131), we get a palindrome (665483727384566).
The spelling of 131441215240435 in words is "one hundred thirty-one trillion, four hundred forty-one billion, two hundred fifteen million, two hundred forty thousand, four hundred thirty-five".
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