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131441245161 = 343813748387
BaseRepresentation
bin111101001101010000…
…0100011101111101001
3110120021100220002022020
41322122200203233221
54123142424321121
6140214442015053
712332144102202
oct1723240435751
9416240802266
10131441245161
1150820179a36
12215834a7489
13c519664815
14650ca765a9
1536446541c6
hex1e9a823be9

131441245161 has 4 divisors (see below), whose sum is σ = 175254993552. Its totient is φ = 87627496772.

The previous prime is 131441245127. The next prime is 131441245183. The reversal of 131441245161 is 161542144131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131441245161 - 218 = 131440983017 is a prime.

It is not an unprimeable number, because it can be changed into a prime (131441245261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21906874191 + ... + 21906874196.

It is an arithmetic number, because the mean of its divisors is an integer number (43813748388).

Almost surely, 2131441245161 is an apocalyptic number.

It is an amenable number.

131441245161 is a deficient number, since it is larger than the sum of its proper divisors (43813748391).

131441245161 is an equidigital number, since it uses as much as digits as its factorization.

131441245161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43813748390.

The product of its digits is 11520, while the sum is 33.

Adding to 131441245161 its reverse (161542144131), we get a palindrome (292983389292).

The spelling of 131441245161 in words is "one hundred thirty-one billion, four hundred forty-one million, two hundred forty-five thousand, one hundred sixty-one".

Divisors: 1 3 43813748387 131441245161