Base | Representation |
---|---|
bin | 1001011001110010101… |
… | …0011000000010000011 |
3 | 120102222011001012001020 |
4 | 2112130222120002003 |
5 | 10121314242103011 |
6 | 202113400440523 |
7 | 14446110366144 |
oct | 2263452300203 |
9 | 512864035036 |
10 | 161542144131 |
11 | 62567368945 |
12 | 27384179143 |
13 | 123058c6644 |
14 | 7b66667acb |
15 | 430705e006 |
hex | 259ca98083 |
161542144131 has 16 divisors (see below), whose sum is σ = 218946679968. Its totient is φ = 105916608000.
The previous prime is 161542144123. The next prime is 161542144151. The reversal of 161542144131 is 131441245161.
It is not a de Polignac number, because 161542144131 - 23 = 161542144123 is a prime.
It is a super-2 number, since 2×1615421441312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 161542144092 and 161542144101.
It is not an unprimeable number, because it can be changed into a prime (161542144111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1627531 + ... + 1723931.
It is an arithmetic number, because the mean of its divisors is an integer number (13684167498).
Almost surely, 2161542144131 is an apocalyptic number.
161542144131 is a deficient number, since it is larger than the sum of its proper divisors (57404535837).
161542144131 is an equidigital number, since it uses as much as digits as its factorization.
161542144131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105622.
The product of its digits is 11520, while the sum is 33.
Adding to 161542144131 its reverse (131441245161), we get a palindrome (292983389292).
The spelling of 161542144131 in words is "one hundred sixty-one billion, five hundred forty-two million, one hundred forty-four thousand, one hundred thirty-one".
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