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131441525455 = 529906493279
BaseRepresentation
bin111101001101010000…
…1101000001011001111
3110120021101102022210111
41322122201220023033
54123143012303310
6140214452020451
712332146350322
oct1723241501317
9416241368714
10131441525455
1150820350589
1221583601727
13c519732286
14650cb0a7b9
1536446ac28a
hex1e9a8682cf

131441525455 has 8 divisors (see below), whose sum is σ = 163168790400. Its totient is φ = 101527247136.

The previous prime is 131441525387. The next prime is 131441525473. The reversal of 131441525455 is 554525144131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131441525455 - 235 = 97081787087 is a prime.

It is a super-2 number, since 2×1314415254552 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 453246495 + ... + 453246784.

It is an arithmetic number, because the mean of its divisors is an integer number (20396098800).

Almost surely, 2131441525455 is an apocalyptic number.

131441525455 is a deficient number, since it is larger than the sum of its proper divisors (31727264945).

131441525455 is an equidigital number, since it uses as much as digits as its factorization.

131441525455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 906493313.

The product of its digits is 240000, while the sum is 40.

Adding to 131441525455 its reverse (554525144131), we get a palindrome (685966669586).

The spelling of 131441525455 in words is "one hundred thirty-one billion, four hundred forty-one million, five hundred twenty-five thousand, four hundred fifty-five".

Divisors: 1 5 29 145 906493279 4532466395 26288305091 131441525455