1314433190146 has 4 divisors (see below), whose sum is σ = 1971649785222. Its totient is φ = 657216595072.

The previous prime is 1314433190143. The next prime is 1314433190183. The reversal of 1314433190146 is 6410913344131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1136699277921 + 177733912225 = 1066161^2 + 421585^2 .

It is a super-2 number, since 2×1314433190146² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1314433190099 and 1314433190108.

It is not an unprimeable number, because it can be changed into a prime (1314433190143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328608297535 + ... + 328608297538.

Almost surely, 2^{1314433190146} is an apocalyptic number.

1314433190146 is a deficient number, since it is larger than the sum of its proper divisors (657216595076).

1314433190146 is an equidigital number, since it uses as much as digits as its factorization.

1314433190146 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 657216595075.

The product of its (nonzero) digits is 93312, while the sum is 40.

The spelling of 1314433190146 in words is "one trillion, three hundred fourteen billion, four hundred thirty-three million, one hundred ninety thousand, one hundred forty-six".