13144332350453 has 4 divisors (see below), whose sum is σ = 13144493658720. Its totient is φ = 13144171042188.

The previous prime is 13144332350423. The next prime is 13144332350497. The reversal of 13144332350453 is 35405323344131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13144332350453 - 2¹⁰ = 13144332349429 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13144332350453.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13144332350423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80531843 + ... + 80694896.

It is an arithmetic number, because the mean of its divisors is an integer number (3286123414680).

Almost surely, 2^{13144332350453} is an apocalyptic number.

It is an amenable number.

13144332350453 is a deficient number, since it is larger than the sum of its proper divisors (161308267).

13144332350453 is an equidigital number, since it uses as much as digits as its factorization.

13144332350453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161308266.

The product of its (nonzero) digits is 777600, while the sum is 41.

Adding to 13144332350453 its reverse (35405323344131), we get a palindrome (48549655694584).

The spelling of 13144332350453 in words is "thirteen trillion, one hundred forty-four billion, three hundred thirty-two million, three hundred fifty thousand, four hundred fifty-three".