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1314444421021 = 5472232402027
BaseRepresentation
bin10011001000001010111…
…111100010011110011101
311122122210220002001211111
4103020022333202132131
5133013440232433041
62443503013422021
7163652105142124
oct23101277423635
94578726061744
101314444421021
114674a8676526
121928b893a911
1396c4a7cb824
1447895aaaabb
15242d2093981
hex1320afe279d

1314444421021 has 4 divisors (see below), whose sum is σ = 1314447370272. Its totient is φ = 1314441471772.

The previous prime is 1314444421019. The next prime is 1314444421033. The reversal of 1314444421021 is 1201244444131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1314444421021 - 21 = 1314444421019 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1314444421321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 653791 + ... + 1748236.

It is an arithmetic number, because the mean of its divisors is an integer number (328611842568).

Almost surely, 21314444421021 is an apocalyptic number.

It is an amenable number.

1314444421021 is a deficient number, since it is larger than the sum of its proper divisors (2949251).

1314444421021 is an equidigital number, since it uses as much as digits as its factorization.

1314444421021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2949250.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 1314444421021 its reverse (1201244444131), we get a palindrome (2515688865152).

The spelling of 1314444421021 in words is "one trillion, three hundred fourteen billion, four hundred forty-four million, four hundred twenty-one thousand, twenty-one".

Divisors: 1 547223 2402027 1314444421021