Base | Representation |
---|---|
bin | 10011001000001011010… |
… | …110011011001000100111 |
3 | 11122122211022100212020122 |
4 | 103020023112123020213 |
5 | 133013443301422023 |
6 | 2443503350152155 |
7 | 163652210136461 |
oct | 23101326331047 |
9 | 4578738325218 |
10 | 1314450420263 |
11 | 467500aa3882 |
12 | 1928ba95265b |
13 | 96c4bb1c386 |
14 | 478967cd131 |
15 | 242d287b2c8 |
hex | 1320b59b227 |
1314450420263 has 4 divisors (see below), whose sum is σ = 1334069083320. Its totient is φ = 1294831757208.
The previous prime is 1314450420181. The next prime is 1314450420289. The reversal of 1314450420263 is 3620240544131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1314450420263 - 228 = 1314181984807 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1314450420863) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9809331428 + ... + 9809331561.
It is an arithmetic number, because the mean of its divisors is an integer number (333517270830).
Almost surely, 21314450420263 is an apocalyptic number.
1314450420263 is a deficient number, since it is larger than the sum of its proper divisors (19618663057).
1314450420263 is an equidigital number, since it uses as much as digits as its factorization.
1314450420263 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19618663056.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 1314450420263 its reverse (3620240544131), we get a palindrome (4934690964394).
The spelling of 1314450420263 in words is "one trillion, three hundred fourteen billion, four hundred fifty million, four hundred twenty thousand, two hundred sixty-three".
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