Base | Representation |
---|---|
bin | 11000011111000001… |
… | …01000011101000001 |
3 | 1020221002212000001010 |
4 | 30033200220131001 |
5 | 203410122130213 |
6 | 10012213231133 |
7 | 643514425533 |
oct | 141740503501 |
9 | 36832760033 |
10 | 13145114433 |
11 | 5636090040 |
12 | 266a3324a9 |
13 | 131647cc29 |
14 | 8c9b41853 |
15 | 51e068ac3 |
hex | 30f828741 |
13145114433 has 8 divisors (see below), whose sum is σ = 19120166496. Its totient is φ = 7966736000.
The previous prime is 13145114429. The next prime is 13145114441. The reversal of 13145114433 is 33441154131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13145114433 - 22 = 13145114429 is a prime.
It is a super-2 number, since 2×131451144332 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13145114433.
It is not an unprimeable number, because it can be changed into a prime (13145114933) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 199168368 + ... + 199168433.
It is an arithmetic number, because the mean of its divisors is an integer number (2390020812).
Almost surely, 213145114433 is an apocalyptic number.
It is an amenable number.
13145114433 is a deficient number, since it is larger than the sum of its proper divisors (5975052063).
13145114433 is a wasteful number, since it uses less digits than its factorization.
13145114433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 398336815.
The product of its digits is 8640, while the sum is 30.
Adding to 13145114433 its reverse (33441154131), we get a palindrome (46586268564).
The spelling of 13145114433 in words is "thirteen billion, one hundred forty-five million, one hundred fourteen thousand, four hundred thirty-three".
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