Search a number
-
+
13145114433 = 311398336801
BaseRepresentation
bin11000011111000001…
…01000011101000001
31020221002212000001010
430033200220131001
5203410122130213
610012213231133
7643514425533
oct141740503501
936832760033
1013145114433
115636090040
12266a3324a9
13131647cc29
148c9b41853
1551e068ac3
hex30f828741

13145114433 has 8 divisors (see below), whose sum is σ = 19120166496. Its totient is φ = 7966736000.

The previous prime is 13145114429. The next prime is 13145114441. The reversal of 13145114433 is 33441154131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13145114433 - 22 = 13145114429 is a prime.

It is a super-2 number, since 2×131451144332 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13145114433.

It is not an unprimeable number, because it can be changed into a prime (13145114933) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 199168368 + ... + 199168433.

It is an arithmetic number, because the mean of its divisors is an integer number (2390020812).

Almost surely, 213145114433 is an apocalyptic number.

It is an amenable number.

13145114433 is a deficient number, since it is larger than the sum of its proper divisors (5975052063).

13145114433 is a wasteful number, since it uses less digits than its factorization.

13145114433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 398336815.

The product of its digits is 8640, while the sum is 30.

Adding to 13145114433 its reverse (33441154131), we get a palindrome (46586268564).

The spelling of 13145114433 in words is "thirteen billion, one hundred forty-five million, one hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 3 11 33 398336801 1195010403 4381704811 13145114433